6(2x^2-5x^2)=0

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Solution for 6(2x^2-5x^2)=0 equation: 



6(2x^2-5x^2)=0

We multiply parentheses

12x^2-30x^2=0

We add all the numbers together, and all the variables

-18x^2=0

a = -18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-18)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-36}=0$

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